Jharkhand 4th Combined Civil Services Physics Paper-II 2012
- Year 2012
- Conducted By Jharkhand Government
- Maximum Marks 200
- Languages English & Hindi
Exam Details
| Detail | Information |
|---|---|
| Examination | 4th Combined Civil Services (Main) Exam |
| Year | 2012 |
| Conducting Body | Jharkhand Government |
| Paper | Physics Paper-II |
| Subject | Physics |
| Maximum Marks | 200 |
| Question Type | Descriptive and objective |
This page hosts the 4th Combined Civil Services (Main) Exam (2012) question paper conducted by Jharkhand Government. Subject: Physics. Maximum marks: 200. Question type: Descriptive and Objective. Read exam instructions and page-2 questions online, or download the official PDF for offline practice.
Major Topics Covered
- 4th Combined Civil Services (Main) Exam
- Physics
- Physics Paper-II
- Jharkhand Government
- 2012 question paper
- previous year paper
- PDF download
Why This Paper is Important
- Useful for 4th Combined Civil Services (Main) Exam preparation
- Helps understand the latest exam pattern
- Useful for practice and self-assessment
- Covers frequently asked General Studies topics
- Helpful for analysing question trends
Related Resources
- 4th Combined Civil Services Main Exam 2012 Paper I Urdu L&L
- JPSC 4th Combined Civil Services Main Exam 2012 Labour & Social Welfare Paper II
- Jharkhand JPSC 4th Combined Civil Services Main Exam 2012 Zoology Paper
- Jharkhand 4th Combined Civil Services Main Exam 2012 Zoology Paper I
- JPSC 4th Combined Civil Services Main Exam 2012 Kurmali Paper-II
Instructions
- Charge of electron, e = 1.6 \times 10^{-19} coulomb त की पारगन्दता, \mu_0 = 4\pi \times 10^{-7} वेकर/एन्मी-गी ^2 प्ट्रॉन का द्रव्यमान, m_e = 9 \cdot 11 \times 10^{-31} कि० ग्रा० न का द्रव्यनान, m_p = 1 \cdot 67 \times 10^{-27} कि० ग्रा० electromagnetic radiation is Mass of electron, m_e = 9 \cdot 11 \times 10^{-31} kg Mass of proton, m_p = 1.67 \times 10^{-27} kg इलेक्ट्रॉन का आतेश, e = 1.6 \times 10^{-19} कूलॉन प्लांक स्थिरांक, h = 6.63 x 10-34 जूल-से० intensity at this point? \begin{array}{c} 12 \\ 1 \end{array} Permeability of free space, *** Permittivity of free space, आयाम क्या होगा? 12Y-100/50 Constants: Ē ত্র \overline{a} က် \ddot{\bm{r}} ທ່ Ġ
Questions (page 2)
Formatted from page 2 OCR. Download the PDF for the full paper.
What is Zeeman effect? Use vector चुम्बकीय सदिश विभव से आप क्या समझते हैं? इसका vector potential? Obtain its vector की व्याख्या किस प्रकार होती है? equation? Write down Einstein's photoelectric ज़ेमान प्रभाव क्या है? वेक्टर मॉडल की सहायता से पाँयसन समीकरण ज्ञात कीजिए तथा इसके हल का व्यंजक समेकरण से प्रकाश-विद्युत् प्रभाव के प्रायोगिक परिणानों आइन्स्टाइन का प्रकाश-विदुत् समीकरण लिखिए। इस सामान्य जेमान विस्थापन के लिए सूत्र प्राप्त कीजिए। model to obtain an expression for its solution. of photoelectric effect explained by this equation. How are experimental results normal Zeeman shift. Poisson equation and hence write down (Continued) p 09/001-X21 Why In a common-base amplilier, the voltage Explain modulation and demodulation, and रेडियो तरंगों की तुलना में सूक्ष्म तरंगें संकेतों के बाहक के dorp रूप में वेहतर क्यों हैं? 0022 मॉडुलन व विमॉडुलन को समझाइए तथा आयान, आवृत्ति than base जज amplitude, धारा का मान ज्ञात कीजिए। (a = 0.9) एक उभयनिष्ठ आधार प्रवर्धक में संग्राहक के साथ जुड़े modulation. with the collector is 2.2 volts. Obtain the give a comparative account of are microwaves considered better current. across a 2200 2 resistor connected radio waves for carrying signals? । माँडुलन का तुलनात्मक विवरण दीजिए Q प्रतिरोध पर वेल्टितापात 2-2 वोल्ट है। आधार frequency and phase (Turn Over) and the construction of the construction of the construction of the construction of the construction of the construction of the construction of the construction of the construction of the (b) A proton of 30 MeV kinetic energy is चुम्बकीय क्षेत्र की दिशा के लम्बवत् गति करता है। प्रोटोन द्वारा तय किये गये पथ की तिज्या तथा घूर्णन काल ज्ञात 30 MeV गतिब ऊर्जा का एक प्रोटॉन 1-5 टेसला वाले period of rotation. path followed by the proton and its time perpendicularly. Find the radius of the moving in a magnetic field of 1.5 T f (b) Prove that the voltage gain of amplifier सिद्ध कीजिए कि पुनर्निवेश के कारण प्रवर्धक की वोल्टता due to feedback is given by the equation meaning. , where symbols have usual ष्ट्र A_f = से दी जाती है, जहाँ संकेतों - - Addition - Andrews - Andrews - Andrews - Andrews - Andrews —ហ
Question paper preview
Scanned pages 1–2 for reference. Download the official PDF for the full paper.
Free question paper download
Download question paper PDF
Your download starts in 10s
Preparing your question paper file…
Frequently asked questions
Where can I download the 4th Combined Civil Services (Main) Exam question paper PDF?
Use the Download PDF button on this page to save the official 4th Combined Civil Services (Main) Exam (2012) Physics Paper-II paper hosted on QuizCurrent.
Who conducts the 4th Combined Civil Services (Main) Exam?
The 4th Combined Civil Services (Main) Exam is conducted by Jharkhand Government. This portal reproduces the scanned question paper for practice and revision.
Does this page include exam instructions and questions?
Yes. Page 1 instructions and page 2 questions are extracted from the official PDF OCR so you can read them without downloading.
How many questions are on this paper?
Refer to the instructions section on page 1 for the total question count and marking scheme.