Indian Forest Service 2020 Mechanical Engineering Paper-II PDF

Central Government Jobs Engineer 2020

  • Year 2020
  • Conducted By UPSC
  • Maximum Marks 200
  • Duration Three Hours
  • Languages English

Exam Details

Detail Information
Examination Indian Forest Service (Main) Examination
Year 2020
Conducting Body UPSC
Paper Mechanical Engineering Paper-II
Subject Mechanical Engineering
Duration Three Hours
Maximum Marks 200
Question Type Mixed

This is the official question paper for the Indian Forest Service (Main) Examination 2020, Paper-II, focusing on Mechanical Engineering. Conducted by UPSC, this paper is designed to assess candidates' in-depth knowledge in the subject. It allows a duration of three hours and carries a maximum of 200 marks. The paper consists of eight questions, out of which five are compulsory, with specific instructions regarding compulsory questions and section selections. Aspirants can use this paper to understand the exam pattern, question types, and difficulty level, crucial for their preparation.

Major Topics Covered

  • Mechanical Engineering
  • Thermodynamics
  • Heat Transfer
  • Internal Combustion Engines
  • Refrigeration
  • Fluid Mechanics
  • Steady Flow Systems
  • Carnot Cycle
  • R12 Properties

Why This Paper is Important

  • Useful for Indian Forest Service (Main) Examination preparation
  • Helps understand the latest exam pattern
  • Useful for practice and self-assessment
  • Covers frequently asked General Studies topics
  • Helpful for analysing question trends

Related Resources

  • Indian Forest Service (Main) Examination 2020 Mechanical Engineering Paper-I
  • Indian Forest Service (Main) Examination 2019 Mechanical Engineering Paper-II
  • Engineering Services Examination 2020 Mechanical Engineering Paper-II
  • Indian Forest Service 2020 Mechanical Engineering Paper-II Answer Key
  • Indian Forest Service Mechanical Engineering Syllabus
  • UPSC Mechanical Engineering Syllabus
  • Indian Forest Service Exam Pattern
  • UPSC Main Exam Pattern

Instructions

  • There are EIGHT questions in all, out of which FIVE are to be attempted.
  • Out of the remaining SIX questions, THREE are to be attempted selecting at least ONE question from each of the two Sections A and B.
  • The number of marks carried by a question/part is indicated against it.
  • Unless otherwise mentioned, symbols and notations have their usual standard meanings.
  • Assume suitable data, if necessary and indicate the same clearly.
  • Neat sketches may be drawn, wherever required.
  • Attempts of questions shall be counted in sequential order.
  • Unless struck off, attempt of a question shall be counted even if attempted partly.
  • Any page or portion of the page left blank in the Question-cum-Answer Booklet must be clearly struck off.
  • Answers must be written in ENGLISH only.
  • Newton may be converted to kgf using the equality 1 kilonewton (1 \text{ kN}) = 100 \text{ kgf}, if found necessary.
  • Take : 1 kcal = 4.187 kJ and 1 kg/cm2 = 0.98 bar 1 bar = 10^5 pascals Universal gas constant = 8314.6 J/kmol-K Psychrometric chart is enclosed.

Questions (page 2)

Section A

Q1.

(a) changes are negligible? How is it different from a closed stationary system? 8 Explain various methods to increase the power output of the IC engines with

(b) 8 same volumetric capacity. The inner and outer surfaces of a spherical container are maintained at |c| temperatures of T1 = 200 °C and T2 = 80 °C, respectively. The container is having the following dimensions : Inner radius = 8 \text cm, outer radius = 10 \text cm The thermal conductivity of the container material is 45 W/m-K. Obtain a general relation for the temperature distribution inside the container under steady conditions and also, determine the rate of heat loss from the container. 8 A Carnot refrigerator has working temperatures of -30 °C and 35 °C. If it

(d) operates with R12 as a working substance, calculate the work of isentropic compression and that of isentropic expansion. Also, calculate the refrigerating effect, heat rejected per kg of the refrigerant and COP of the cycle. 8 Thermodynamic properties of R12 Satura- Satura- Vapour Superheated Saturated Liquid and Vapour tion tion By 40 °C By 20 °C Temp. Pressure h h s s hf sg t ηg sf p vf vg (1)/((m3 / kg)) (kJ/kg) (kJ/kg) (kJ/ (kJ/kg) (kJ/ (kJ/kg) (kJ/ (kJ/kg) (kJ/ (\circC) (bar) kg-K) kg-K) kg-K) kg-K) 0.8178 0.7737 192 - 4 0.7274 180 - 8 0.66 0.2421 169.0 0 0 0.6417 -40 0.8120 0.7220 183.3 0.7681 195 - 1 171-9 0.0187 0.8069 0.67 0.1950 4 - 4 -35 197.8 0.8068 0.7631 174.2 0.0371 0.7171 185 - 8 1.0038 0.67 0.1595 8-9 -30 200-4 0.8021 0.7127 188.3 0.7586 176 - 5 0.0552 1.2368 0.68 0.1313 13-3 -25 0.7979 190.8 0.7546 203-1 0.7088 178 - 7 0.0731 1.5089 0.69 0.1089 17-8 -20 0.7942 0.7052 193.2 0.7510 205 - 7 22.3 1810 0.0906 0.0911 1.8256 0.69 -15 0.7909 195 - 7 0.7477 208-3 0.7020 183 - 2 0.1080 2.1912 0.70 0.0767 26.9 -10 210-9 0.7879 0.6991 198 - 1 0.7449 0.71 31 - 4 185-4 0.1251 0.0650 2.610 -5 0.7423 213.5 0.7853 0.6966 200-5 0.72 187 - 5 0.1420 3.086 0.0554 36-1 0 202 - 9 0.7401 216-1 0.7830 0.6942 0.72 189.7 0.1587 3.626 0.0475 40.7 5 218.6 0.7810 0.1752 0.6921 205 - 2 0.7381 0.0409 45.4 191 - 7 4.233 0.73 10 0.7792 0.6902 207.5 0.7363 221 - 2 0.0354 193.8 0.1915 4.914 0.74 50-1 15 0.7777 223 - 7 0.2078 0.6885 209.8 0.7348 0.75 0.0308 54.9 195-8 5.673 20 0.7334 226.1 0.7763 0.2239 0.6869 212.1 197 - 7 0.76 0.0269 59.7 6.516 25 0.7751 214-3 228 - 6 0.77 0.2399 0.6854 0.7321 7-450 0.0235 64.6 199.6 30 0.7310 231 - 0 0.7741 201 - 5 0.6839 216 - 4 0.79 0.0206 69.5 0.2559 8.477 35 0.7300 233-4 0.7732 0.6825 218.5 0.80 74 6 203-2 0.2718 9.607 0.0182 40 0.7724 0.6812 220.6 0.7291 235 - 7 0.81 0.0160 79.7 204.9 0.2877 10.843 45 0.3037 222.6 0.7282 238.0 0.7718 0.83 84.9 206 - 5 0.6797 0.0142 12.193 50 226 - 4 0.7265 242 - 4 0.7706 209.3 0.6777 95-7 0.3358 15.259 0.86 0.0111 60 230 - 2 246.2 0.7650 211-5 0.7240 0.90 0.0087 107 - 1 0.3686 0.6738 18.859 70 \overlinea JKLO–B–MCHE/61

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Frequently asked questions

What is the name of the examination?

The examination is the Indian Forest Service (Main) Examination.

Which paper is this question paper for?

This is for Mechanical Engineering Paper-II.

What is the conducting body for this exam?

The conducting body is UPSC (Union Public Service Commission).

What is the year of this question paper?

The year is 2020.

What is the maximum marks for this paper?

The maximum marks for this paper are 200.

What is the time allowed to complete this paper?

The time allowed is Three Hours.

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