BPSC CCE 2025 Mathematics Question Paper PDF

Bihar Government Jobs Administrative / Civil Services 2025

  • Year 2025
  • Conducted By BPSC
  • Maximum Marks 300
  • Duration 3 Hours
  • Languages Hindi & English

Exam Details

Detail Information
Examination Combined Competitive Examinations (CCE)
Year 2025
Conducting Body BPSC
Paper Mathematics
Subject Mathematics
Duration 3 Hours
Maximum Marks 300
Question Type Mixed

This document contains the Mathematics paper for the Combined Competitive Examinations (CCE) conducted by BPSC in 2025. The paper is divided into sections and includes a mix of objective and descriptive questions, testing various mathematical concepts. With a duration of 3 hours and a maximum of 300 marks, this paper is crucial for aspirants aiming for administrative roles. Practicing with this paper helps candidates understand the exam pattern, difficulty level, and important topics, thereby improving their preparation strategy for the BPSC CCE.

Major Topics Covered

  • Linear Algebra
  • Polynomials
  • Vector Spaces
  • Basis and Dimension
  • Matrix Algebra
  • Diagonalization
  • Geometry
  • Sphere Volume
  • Vector Calculus
  • Curl and Gradient
  • Integral Calculus
  • Beta and Gamma Functions
  • Differential Equations
  • Space Curves
  • Curvature and Torsion
  • Tensor Algebra

Why This Paper is Important

  • Useful for Combined Competitive Examinations (CCE) preparation
  • Helps understand the latest exam pattern
  • Useful for practice and self-assessment
  • Covers frequently asked General Studies topics
  • Helpful for analysing question trends

Related Resources

  • BPSC CCE 2025 General Studies Paper
  • BPSC CCE 2024 Mathematics Question Paper
  • BPSC Assistant Engineer Mathematics Paper
  • BPSC CCE 2025 Mathematics Answer Key
  • BPSC CCE 2024 Mathematics Answer Key
  • BPSC CCE Syllabus
  • BPSC Mathematics Syllabus
  • BPSC CCE Exam Pattern

Instructions

  • p_1(x) = x^3 - 2x^2 + 4x + 1 p_2(x) = 2x^3 - 3x^2 + 9x - 1 p_3(x) = x^3 + 6x - 5 p_4(x) = 2x^3 - 5x^2 + 7x + 5 then find the basis of W and dimension of W. यदि W बहुपदों से जनित एक स्थान है p_1(x) = x^3 - 2x^2 + 4x + 1 (00-5:25) p_2(x) = 2x^3 - 3x^2 + 9x - 1 TODAS (TO p_3(x) = x^3 + 6x - 5 p_4(x) = 2x^3 - 5x^2 + 7x + 5 तब W का आधार और उसकी विमा ज्ञात कीजिए ।

Questions (page 2)

Q2. (a) Prove that ∫_0^π/2 dθ = ((m + 1)/(2) (n + 1)/(2))/((1/1) (m + n + 2)/(2)); m, n > 0 where √(1/2 (m + n + 2)/(2)) सिद्ध कीजिए ∫_0^π/2 \, dθ = ((m + 1)/(2) (n + 1)/(2))/(2 ((m + n + 2))/(2)); m, n > 0 जहाँ \lceil गामा फल है ।

  • (a) Compute the Fernet frame \T, N, B\, curvature k and torsion \tau, of the space curve below: α(θ) = (6 cos 2θ cos3 (2θ)/(3)), 6 sin 2θ cos3 (2θ)/(3)), 1/2 cos 4θ - cos2 2θ) when θ ∈ 0, (π)/(4)). निम्नलिखित स्पेस वक्र का फर्नेट फ्रेम T, N, B, वक्रता k और टारिसन T, ज्ञात कीजिए, α(θ) = (6 cos 2θ cos3(2θ)/(3)), 6 sin 2θ cos3(2θ)/(3)), 1/2 cos 4θ - cos2 2θ) जहाँ θ ∈ 0, (π)/(4)) (25x2 = 50) Or/अथवा
  • (b) Solve the differential equation (d2y)/(dx2) - (4)/(x + a) (dy)/(dx) + (6)/((x + a)2) y = (x)/((x + a)2); a > 0 अवकल समीकरण को हल कीजिए, a > 0 (d2y)/(dx2) - (4)/(x + a) (dy)/(dx) + (6)/((x + a)2) y = (x)/((x + a)2) Prove that a quantity which on inner multiplication by an arbitrary vector
  • (c) always gives a tensor, is itself a tensor. सिद्ध कीजिए एक राशि जिसे एक स्वेच्छ सदिश से आंतर गुणन करने पर एक टेन्सर प्राप्त होता है, स्वयं एक टेन्सर है । स्वाम के अन्नडाई स्वाम के प्राप्त को प्रसार को प्राप्त कर रहा है । (25x2 = 50) ा करीति कामी कि उन्ने कापको केंद्र पर सम्मा ने लिए अध्यक्ष समाज के लिए \mathbbE \|\mathbfyi\|\mathcalF^2 + \|\mathbfyi\|\mathcalF^2 ] = \mathbbE \|\nabla \mathbfyi\|\mathcalF\|\mathbfyi\|\mathcalF^2 + \overline\mathbfA2\|\mathbfyi\|\mathcalF+ \mathbfA \|\mathbfyi\|\mathcalF^2 ] Earth (Continued)
  • (d) 02/GO/CC/M-2025-45

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Frequently asked questions

What is the name of the exam?

The exam is the Combined Competitive Examinations (CCE).

Which conducting body organizes this exam?

The Bihar Public Service Commission (BPSC) conducts this examination.

What is the subject of this question paper?

The subject is Mathematics.

What is the maximum marks for the Mathematics paper?

The maximum marks for the paper are 300.

What is the time duration allowed for the exam?

The allowed time duration is 3 Hours.

What is the paper code?

The paper code is M-2025.

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