Q1. A 4 bit synchronous counter uses flip flop with propagation delay time of 25 ns each. The maximum possible time required for change of state will be :
- (1) 25 ns
- (2) 50 ns
- (3) 75 ns
- (4) 100 ns
| Detail | Information |
|---|---|
| Examination | RAJ. STATE ELIGIBILITY TEST |
| Year | 2013 |
| Conducting Body | RPSC |
| Paper | Computer Science and Application (Paper- II) |
| Subject | Computer Science & Application |
| Duration | 1.25 Hours |
| Maximum Marks | 100 |
| Number of Questions | 50 |
| Question Type | Objective (MCQ) |
This is the official question paper for the RAJ SET 2013 examination, specifically for Computer Science and Application (Paper- II), conducted by RPSC. The paper consists of 50 objective questions designed to test candidates' knowledge in Computer Science and Application. With a maximum mark of 100 and a time duration of 1.25 hours, this paper is crucial for aspirants preparing for the Rajasthan State Eligibility Test. Analyzing this paper helps understand the exam pattern, difficulty level, and important topics covered.
Scanned pages 1–2 for reference. Download the official PDF for the full paper.
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The full name of the exam is RAJ. STATE ELIGIBILITY TEST.
This question paper is from the year 2013.
The RAJ SET 2013 exam was conducted by RPSC.
The subject of this paper is Computer Science & Application (Paper- II).
The paper code is 204.
There are 50 questions in this paper.