| Detail | Information |
|---|---|
| Examination | Indian Forest Service (Main) Examination |
| Year | 2019 |
| Conducting Body | UPSC |
| Paper | Physics Paper - II |
| Subject | Physics |
| Duration | Three Hours |
| Maximum Marks | 200 |
| Number of Questions | 8 |
| Question Type | Mixed |
This is the Physics Paper II question paper for the Indian Forest Service (Main) Examination held in 2019 by UPSC. The paper carried a maximum of 200 marks and candidates were allowed three hours to complete it. It consists of eight questions, of which five are to be attempted, with compulsory questions and choices from two sections. This paper is crucial for aspirants preparing for the IFS exam, offering insights into the types of questions asked and the exam pattern. This previous year Indian Forest Service (Main) Examination question paper (2019) is useful for Other Jobs aspirants preparing for Central government recruitment. The paper was conducted by UPSC and reflects the official exam pattern, marking scheme and difficulty level seen in recent cycles. Use it for timed practice, topic-wise revision and understanding how questions are framed in the real examination. Download the free PDF on QuizCurrent to read instructions, attempt MCQs and compare your answers with the study notes provided on this page. Key syllabus areas include Physics, Indian Forest Service, UPSC, Competitive Exams. Useful for Indian Forest Service (Main) Examination preparation. Helps understand the latest exam pattern. Useful for practice and self-assessment.
(a) Calculate the binding energy per nucleon for ^{12}_{6}C nucleus. Given m(^{12}_{6}C) = 12.00000 u, m(p) = 1.00727 u and m(n) = 1.00866 u.
(b) Calculate the energy released in the reaction p + ^{2}_{1}H ightarrow ^{3}_{2}He. Given m(p) = 1.00727 u, m(^{2}_{1}H) = 2.014022 u and m(^{3}_{2}He) = 3.0160500 u.
(c) Calculate the energy released in the reaction ^{16}_{8}O ightarrow 2 lpha. Given m(^{16}_{8}O) = 15.999 u and m(^{4}_{2}He) = 4.002603 u.
Scanned pages 1–2 for reference. Download the official PDF for the full paper.
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The exam is the Indian Forest Service (Main) Examination.
This question paper is from the year 2019.
The examination is conducted by UPSC (Union Public Service Commission).
This paper is Physics Paper - II.
The maximum marks for Physics Paper - II is 200.
The time allowed for this paper is Three Hours.
