Indian Forest Service 2020 Chemical Engineering Paper II PDF

Central Government Jobs Engineer 2020

  • Year 2020
  • Conducted By UPSC
  • Questions 8
  • Maximum Marks 200
  • Duration Three Hours
  • Languages English

Exam Details

Detail Information
Examination Indian Forest Service (Main) Examination
Year 2020
Conducting Body UPSC
Paper Chemical Engineering Paper-II
Subject Chemical Engineering
Duration Three Hours
Maximum Marks 200
Number of Questions 8
Question Type Mixed

This document contains the Chemical Engineering Paper-II for the Indian Forest Service (Main) Examination 2020, conducted by UPSC. The paper is designed to assess candidates' in-depth knowledge of chemical engineering principles. It allows a time duration of Three Hours and carries a maximum of 200 marks. The paper consists of eight questions, of which five are to be attempted, with questions 1 and 5 being compulsory. Candidates must select at least one question from each of the two sections (A and B) from the remaining six questions. Answers are to be written in English only. This paper is crucial for aspirants aiming for a career in forest services with a specialization in chemical engineering.

Major Topics Covered

  • Wet bulb and dry bulb temperatures
  • Oxidation of acid
  • Limestone composition and calculation of CaO
  • Equations of state for real gases
  • Variable volume batch reactor
  • Degree of dissociation
  • Gaseous mixture composition
  • Molar density
  • Enthalpy of gaseous component
  • Air/fuel ratio calculation
  • Combustion

Why This Paper is Important

  • Useful for Indian Forest Service (Main) Examination preparation
  • Helps understand the latest exam pattern
  • Useful for practice and self-assessment
  • Covers frequently asked General Studies topics
  • Helpful for analysing question trends

Related Resources

  • Indian Forest Service (Main) Examination 2019 Chemical Engineering Paper-II
  • Indian Forest Service (Main) Examination 2021 Chemical Engineering Paper-II
  • UPSC Engineering Services Examination Chemical Engineering Paper I
  • UPSC Engineering Services Examination Chemical Engineering Paper II
  • Indian Forest Service (Main) Examination 2020 Chemical Engineering Paper II Answer Key
  • Indian Forest Service (Main) Examination Syllabus
  • Chemical Engineering Syllabus for UPSC Exams
  • Indian Forest Service (Main) Examination Pattern

Instructions

  • There are EIGHT questions in all, out of which FIVE are to be attempted.
  • Out of the remaining SIX questions, THREE are to be attempted selecting at least ONE question from each of the two Sections A and B.
  • The number of marks carried by a question/part is indicated against it.
  • Unless otherwise mentioned, symbols and notations have their usual standard meanings.
  • Assume suitable data, if necessary and indicate the same clearly.
  • Neat sketches may be drawn, wherever required.
  • Attempts of questions shall be counted in sequential order.
  • Unless struck off, attempt of a question shall be counted even if attempted partly.
  • Any page or portion of the page left blank in the Question-cum-Answer Booklet must be clearly struck off.
  • Answers must be written in ENGLISH only.

Questions (page 2)

Section A

Q1.

(a) Define 'wet bulb' and 'dry bulb' temperatures. Dry mixture of HCl gas and air is passed over a heated catalyst, which promotes oxidation of acid. Air is used in 20% excess of that theoretically required. Calculate the weight of air supplied per kg of acid.

(b) A sample of limestone has CaCO3 (84% w/w), MgCO3 (12% w/w) and inert (4% w/w). Calculate the weight of CaO, obtained by 250 kg of sample limestone.

(c) Explain the need of equations of state for real gases, and discuss the limiting conditions that should be satisfied by an equation of state.

(d) For a reaction A ightarrow 4R, occurring in a variable volume batch reactor, derive the following expression: CA = CA0 (1 - XA)/(1 + \varepsilonA XA) ) where CA0 and CA are concentrations at t = 0 and time t; arepsilonA is fractional change in volume; XA is the conversion.

(e) What is degree of dissociation? A vessel has one mole N2O4 at 27 °C and one atmospheric pressure. The dissociation reaction takes place as N2O4 ightleftharpoons 2NO2. Calculate the degree of dissociation, if Kp for the above reaction is 0.

Section A

Q2.

(a) A 500 lit/s of gaseous mixture of the following composition (v/v) is at 27 °C and 2000 mm Hg gauge : CH4 = 20%, C2H6 = 30%, H2 = 50% Calculate-
(i) the mole fraction of each component;
(ii) the molar density of the mixture.

(b) Discuss the term 'enthalpy of gaseous component'. C8H_{18} is burnt with 20% excess air. Calculate the air/fuel ratio by weight. The average molecular weight of air is 28.

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Frequently asked questions

What is the full name of the exam?

The full name of the exam is the Indian Forest Service (Main) Examination.

Which year is this question paper for?

This question paper is for the Indian Forest Service (Main) Examination, 2020.

Who conducts the Indian Forest Service Examination?

The Indian Forest Service Examination is conducted by UPSC (Union Public Service Commission).

What is the subject of this paper?

This paper is for Chemical Engineering, specifically Paper-II.

What is the paper code?

The paper code is JKLO-B-CHME.

What is the time duration allowed for this paper?

The time allowed for this paper is Three Hours.

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