What is the marking penalty for a wrong answer?

One-third of the marks assigned to that question.

Where should responses be marked?

Only on the separate Answer Sheet; do not mark on the Test Booklet.

Where can the PDF be accessed according to the OCR?

http://localhost/quizcurrent.com/question-papers/region/central-government-jobs/engineer/pdf/411

Does the OCR mention a disease D example?

Yes, it references 0.1% of the population having disease D in a screening context.

Engineering Services Prelim 2024 Paper I: General Studies & Aptitude

Central Government Jobs Engineer 2024

Year 2024
Conducted By UPSC
Questions 100
Maximum Marks 200
Duration Two Hours

Exam Details

Detail	Information
Examination	Engineering Services (Preliminary) Examination
Year	2024
Conducting Body	UPSC
Paper	General Studies and Engineering Aptitude
Subject	General Studies and Engineering Aptitude
Duration	Two Hours
Maximum Marks	200
Number of Questions	100
Question Type	Objective (MCQ)

This document corresponds to Paper I of the Engineering Services (Preliminary) Examination for 2024, focusing on General Studies and Engineering Aptitude. Page 1 provides the exam header, timing, total marks (200), and the fact that the test booklet contains 100 questions with four options each. Instructions discuss how to fill the OMR, handling of the answer sheet, and penalty rules for wrong answers. Page 2 (after OCR repair) presents objective-type questions, including topics on exponential distributions and joint densities, and a z-transform question related to sampling a continuous-time signal. The page also shows the need to repair OCR artifacts and split merged questions. The corrected questions extracted from Page 2 include four MCQs, with multiple choices, illustrating the typical content density of the General Studies and Engineering Aptitude paper.

Major Topics Covered

General Studies
Engineering Aptitude
Probability
Statistics
Exponential Distribution
Joint Density
Marginal Density
Z-transform
Digital Signal Processing
Sampling
MCQ
Test Booklet Instructions
Answer Sheet Handling
Marking Scheme
Penalty Rules
Paper I
Engineering Services
Preliminary
GC/ES 2024
Bilingual Assessment Notes

Why This Paper is Important

Useful for Engineering Services (Preliminary) Exami preparation
Helps understand the latest exam pattern
Useful for practice and self-assessment
Covers frequently asked General Studies topics
Helpful for analysing question trends

Related Resources

Instructions

CHECK THAT THIS TEST BOOKLET DOES NOT HAVE ANY UNPRINTED OR TORN OR MISSING PAGES OR ITEMS, ETC.
IF SO, GET IT REPLACED BY A COMPLETE TEST BOOKLET.
PLEASE NOTE THAT IT IS THE CANDIDATE'S RESPONSIBILITY TO ENCODE AND
FILL IN THE ROLL NUMBER AND TEST BOOKLET SERIES CODE A, B, C OR D CAREFULLY AND WITHOUT ANY OMISSION OR DISCREPANCY AT THE APPRO- PRIATE PLACES IN THE OMR ANSWER SHEET.
ANY OMISSION/DISCREPANCY WILL RENDER THE ANSWER SHEET LIABLE FOR REJECTION.
You have to enter your Roll Number on the Test
DO NOT write anything else on the Test Booklet.
This Test Booklet contains 100 items (questions).
Each item comprises four responses (answers).
will select the response which you want to mark on the Answer Sheet.
In case, you feel that there is more than one correct response, mark the response which you consider the best.
In any case, choose ONLY ONE response for each item.
You have to mark your responses ONLY on the separate Answer Sheet provided.
in the Answer Sheet. All items carry equal marks.
Before you proceed to mark in the Answer Sheet the response to various items in the Test Booklet,
you have to fill in some particulars in the Answer Sheet as per instructions sent to you with your Admission Certificate.
After you have completed filling in all your responses on the Answer Sheet and the examination has concluded, you should hand over to the Invigilator only the Answer Sheet.
You are permitted to take away with you the Test Booklet.
Sheets for rough work are appended in the Test Booklet at the end.
Penalty for wrong Answers: THERE WILL BE PENALTY FOR WRONG ANSWERS MARKED BY A CANDIDATE.

Questions (page 2)

Q1.

(a) The standard deviation of the expo-
3. Let the random variables X and Y have nential distribution of joint density function given by f_X
(x) = \begincases λ e^{-λ x}, & x ≥ 0 \\ 0, & x < 0 \endcases is f_X,Y(x,y) = \begincases c(1-y), & 0 ≤ x ≤ y ≤ 1 \\ 0, & \textotherwise \endcases Then the marginal density function for (1)/(λ) X is (a) f_X
(x) = 61/2-x-(x²)/(2)) for 0 ≤ x ≤ 1
(b) (2)/(λ^2)
(c) (3)/(2³) (b) f_X
(x) = 61/2 + x + (x²)/(2)) for 0 ≤ x ≤ 1
(d) (2)/(3³)
(c) f_X
(x) = 61/2 + x-(x²)/(2)) for 0 ≤ x ≤ 1

Q2.

(a) Suppose that 0.1\% of the people in a certain area have a disease D and that a mass screening test is used to detect cases. The test gives either a positive (d) f_X
(x) = 61/2-x + (x²)/(2)) for 0 ≤ x ≤ 1 or a negative result for each person. Ideally, the test would always give a positive result for a person who has D, and would never do so for a person
4. The continuous-time signal f(t) = e^{-2ω t}, who has not. In practice the test gives where ω is a real constant, is sampled a positive result with probability when t ≥ 0 at intervals T. What is the 99.9% for a person who has D, and z transform of the resulting sequence with probability 0.2\% for a person of samples ? who has not. What is the probability that a person for whom the test is (z)/(z - e^{-2ω T}) positive actually has the disease? (a) 1/3
(b) (z)/(1 - e^{-2ω T}) (b) (5/3)
(c) (z)/(z - e^{-ω T})
(c) (4/3)
(d) 2/3 (d) (z)/(z - e^{2ω T}) PNGE-U-GEA - A \overline2

Q3. 3. Let the random variables X and Y have exponential distribution of joint density function given by f_X
(x) = { λ e^{−λ x}, x ≥ 0; 0, x < 0 } and f_{X,Y}(x,y) = { c(1−y), 0 ≤ x ≤ y ≤ 1; 0, otherwise }. Then the marginal density function for X is

(a) f_X(x) = 6(1/2 - x - x²/2) for 0 ≤ x ≤ 1
(b) 2/λ^2
(c) 3/2^3
(d) f_X(x) = 6(1/2 + x + x²/2) for 0 ≤ x ≤ 1

Q4. 4. The continuous-time signal f(t) = e^{−2ω t}, ω real, is sampled at intervals T. What is the z-transform of the resulting sequence if the samples are taken with probability 0.2% for a person who has D and 99.9% for a person who has not?

(a) z/(z − e^{−2ω T})
(b) z/(1 − e^{−2ω T})
(c) z/(z − e^{−ω T})
(d) z/(z − e^{2ω T})

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Frequently asked questions

What is the exam name?

Engineering Services (Preliminary) Examination.

Which paper is described here?

Paper I: General Studies and Engineering Aptitude.

What year is this paper from?

2024.

What is the duration of the exam?

Two hours.

What is the maximum marks for Paper I?

200 marks.

How many items are in the test booklet?

100 items.

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